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4x^2-5x(x+6)=2x+3
We move all terms to the left:
4x^2-5x(x+6)-(2x+3)=0
We multiply parentheses
4x^2-5x^2-30x-(2x+3)=0
We get rid of parentheses
4x^2-5x^2-30x-2x-3=0
We add all the numbers together, and all the variables
-1x^2-32x-3=0
a = -1; b = -32; c = -3;
Δ = b2-4ac
Δ = -322-4·(-1)·(-3)
Δ = 1012
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1012}=\sqrt{4*253}=\sqrt{4}*\sqrt{253}=2\sqrt{253}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-2\sqrt{253}}{2*-1}=\frac{32-2\sqrt{253}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+2\sqrt{253}}{2*-1}=\frac{32+2\sqrt{253}}{-2} $
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