4(x+2)=5(x+1)+9(x+3)

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Solution for 4(x+2)=5(x+1)+9(x+3) equation: 



4(x+2)=5(x+1)+9(x+3)

We move all terms to the left:

4(x+2)-(5(x+1)+9(x+3))=0

We multiply parentheses

4x-(5(x+1)+9(x+3))+8=0



We calculate terms in parentheses: -(5(x+1)+9(x+3)), so:

5(x+1)+9(x+3)

We multiply parentheses

5x+9x+5+27

We add all the numbers together, and all the variables

14x+32

Back to the equation:

-(14x+32)



We get rid of parentheses

4x-14x-32+8=0

We add all the numbers together, and all the variables

-10x-24=0

We move all terms containing x to the left, all other terms to the right

-10x=24

x=24/-10

x=-2+2/5

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