(2x-8)(2x+10)=4x2-64

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Solution for (2x-8)(2x+10)=4x2-64 equation: 



(2x-8)(2x+10)=4x^2-64

We move all terms to the left:

(2x-8)(2x+10)-(4x^2-64)=0

We get rid of parentheses

-4x^2+(2x-8)(2x+10)+64=0

We multiply parentheses ..

-4x^2+(+4x^2+20x-16x-80)+64=0

We get rid of parentheses

-4x^2+4x^2+20x-16x-80+64=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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