(X-4)(x+5)=x2-17

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Solution for (X-4)(x+5)=x2-17 equation: 



(X-4)(X+5)=X2-17

We move all terms to the left:

(X-4)(X+5)-(X2-17)=0

We add all the numbers together, and all the variables

-(+X^2-17)+(X-4)(X+5)=0

We get rid of parentheses

-X^2+(X-4)(X+5)+17=0

We multiply parentheses ..

-X^2+(+X^2+5X-4X-20)+17=0

We add all the numbers together, and all the variables

-1X^2+(+X^2+5X-4X-20)+17=0

We get rid of parentheses

-1X^2+X^2+5X-4X-20+17=0

We add all the numbers together, and all the variables

X-3=0

We move all terms containing X to the left, all other terms to the right

X=3

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