5/7(t+7)=2/7(t+23)

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Solution for 5/7(t+7)=2/7(t+23) equation: 



5/7(t+7)=2/7(t+23)

We move all terms to the left:

5/7(t+7)-(2/7(t+23))=0



Domain of the equation: 7(t+7)!=0

t∈R





Domain of the equation: 7(t+23))!=0

t∈R



We calculate fractions


(35tt/(7(t+7)*7(t+23)))+(-14tt/(7(t+7)*7(t+23)))=0



We calculate terms in parentheses: +(35tt/(7(t+7)*7(t+23))), so:

35tt/(7(t+7)*7(t+23))

We multiply all the terms by the denominator


35tt

Back to the equation:

+(35tt)





We calculate terms in parentheses: +(-14tt/(7(t+7)*7(t+23))), so:

-14tt/(7(t+7)*7(t+23))

We multiply all the terms by the denominator


-14tt

Back to the equation:

+(-14tt)



We get rid of parentheses

35tt-14tt=0

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