(6/7)t-12=(3/14)t+15

Solution for (6/7)t-12=(3/14)t+15 equation:

(6/7)t-12=(3/14)t+15

We move all terms to the left:

(6/7)t-12-((3/14)t+15)=0


Domain of the equation: 7)t!=0

t!=0/1

t!=0

t∈R



Domain of the equation: 14)t+15)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

(+6/7)t-((+3/14)t+15)-12=0

We multiply parentheses

6t^2-((+3/14)t+15)-12=0

We multiply all the terms by the denominator


6t^2*14)t+15)-((-12*14)t+15)+3=0

We add all the numbers together, and all the variables

6t^2*14)t+15)-((-168)t+15)+3=0

Wy multiply elements

84t^3-168)t+15)+3=0

We do not support etpression: t^3