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(2x-3)/(3x+2)=-2/3
We move all terms to the left:
(2x-3)/(3x+2)-(-2/3)=0
Domain of the equation: (3x+2)!=0We get rid of parentheses
We move all terms containing x to the left, all other terms to the right
3x!=-2
x!=-2/3
x!=-2/3
x∈R
(2x-3)/(3x+2)+2/3=0
We calculate fractions
(6x-9)/(9x+6)+(6x+4)/(9x+6)=0
We multiply all the terms by the denominator
(6x-9)+(6x+4)=0
We get rid of parentheses
6x+6x-9+4=0
We add all the numbers together, and all the variables
12x-5=0
We move all terms containing x to the left, all other terms to the right
12x=5
x=5/12
x=5/12
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