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X(2X-12)=432
We move all terms to the left:
X(2X-12)-(432)=0
We multiply parentheses
2X^2-12X-432=0
a = 2; b = -12; c = -432;
Δ = b2-4ac
Δ = -122-4·2·(-432)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-60}{2*2}=\frac{-48}{4} =-12 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+60}{2*2}=\frac{72}{4} =18 $
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