7-3/2(-6x+4)=10+4(-4x-5)

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Solution for 7-3/2(-6x+4)=10+4(-4x-5) equation: 



7-3/2(-6x+4)=10+4(-4x-5)

We move all terms to the left:

7-3/2(-6x+4)-(10+4(-4x-5))=0



Domain of the equation: 2(-6x+4)!=0

x∈R



We multiply all the terms by the denominator


-((10+4(-4x-5)))*2(-6x+4)+7*2(-6x+4)-3=0



We calculate terms in parentheses: -((10+4(-4x-5)))*2(-6x+4), so:

(10+4(-4x-5)))*2(-6x+4

We add all the numbers together, and all the variables

-6x+(10+4(-4x-5)))*2(+4

Back to the equation:

-(-6x+(10+4(-4x-5)))*2(+4)



We add all the numbers together, and all the variables

-(-6x+(10+4(-4x-5)))*24+7*2(-6x+4)-3=0

Wy multiply elements

-(-6x+(10+4(-4x-5)))*24+14x(--3=0

We use the square of the difference formula

-(-6x+(10+4(-4x-5)))*24+14x(+3=0

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