1.10=x(x+1)=2x+1

Solution for 1.10=x(x+1)=2x+1 equation:

1.10=x(x+1)=2x+1

We move all terms to the left:

1.10-(x(x+1))=0

We add all the numbers together, and all the variables

-(x(x+1))+1.1=0


We calculate terms in parentheses: -(x(x+1)), so:

x(x+1)

We multiply parentheses

x^2+x

Back to the equation:

-(x^2+x)


We get rid of parentheses

-x^2-x+1.1=0

We add all the numbers together, and all the variables

-1x^2-1x+1.1=0

a = -1; b = -1; c = +1.1;
Δ = b2-4ac
Δ = -12-4·(-1)·1.1
Δ = 5.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{5.4}}{2*-1}=\frac{1-\sqrt{5.4}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{5.4}}{2*-1}=\frac{1+\sqrt{5.4}}{-2}
$