(2x+3)/6+(2x+3)/3=1/2

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Solution for (2x+3)/6+(2x+3)/3=1/2 equation: 



(2x+3)/6+(2x+3)/3=1/2

We move all terms to the left:

(2x+3)/6+(2x+3)/3-(1/2)=0

We add all the numbers together, and all the variables

(2x+3)/6+(2x+3)/3-(+1/2)=0

We get rid of parentheses

(2x+3)/6+(2x+3)/3-1/2=0

We calculate fractions

There is no solution for this equation

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