-6(9x+5)3x+4x=-408-x

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Solution for -6(9x+5)3x+4x=-408-x equation:



-6(9x+5)3x+4x=-408-x
We move all terms to the left:
-6(9x+5)3x+4x-(-408-x)=0
We add all the numbers together, and all the variables
-6(9x+5)3x+4x-(-1x-408)=0
We add all the numbers together, and all the variables
4x-6(9x+5)3x-(-1x-408)=0
We multiply parentheses
-162x^2+4x-90x-(-1x-408)=0
We get rid of parentheses
-162x^2+4x-90x+1x+408=0
We add all the numbers together, and all the variables
-162x^2-85x+408=0
a = -162; b = -85; c = +408;
Δ = b2-4ac
Δ = -852-4·(-162)·408
Δ = 271609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-\sqrt{271609}}{2*-162}=\frac{85-\sqrt{271609}}{-324} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+\sqrt{271609}}{2*-162}=\frac{85+\sqrt{271609}}{-324} $

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