2(y-3)=2(y-9)+2y

Solution for 2(y-3)=2(y-9)+2y equation:

2(y-3)=2(y-9)+2y

We move all terms to the left:

2(y-3)-(2(y-9)+2y)=0

We multiply parentheses

2y-(2(y-9)+2y)-6=0


We calculate terms in parentheses: -(2(y-9)+2y), so:

2(y-9)+2y

We add all the numbers together, and all the variables

2y+2(y-9)

We multiply parentheses

2y+2y-18

We add all the numbers together, and all the variables

4y-18

Back to the equation:

-(4y-18)


We get rid of parentheses

2y-4y+18-6=0

We add all the numbers together, and all the variables

-2y+12=0

We move all terms containing y to the left, all other terms to the right

-2y=-12

y=-12/-2

y=+6