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(2x+3)/5=x+6
We move all terms to the left:
(2x+3)/5-(x+6)=0
We get rid of parentheses
(2x+3)/5-x-6=0
We multiply all the terms by the denominator
(2x+3)-x*5-6*5=0
We add all the numbers together, and all the variables
(2x+3)-x*5-30=0
Wy multiply elements
(2x+3)-5x-30=0
We get rid of parentheses
2x-5x+3-30=0
We add all the numbers together, and all the variables
-3x-27=0
We move all terms containing x to the left, all other terms to the right
-3x=27
x=27/-3
x=-9
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