5c-4(c-7)=3+2c

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Solution for 5c-4(c-7)=3+2c equation: 



5c-4(c-7)=3+2c

We move all terms to the left:

5c-4(c-7)-(3+2c)=0

We add all the numbers together, and all the variables

5c-4(c-7)-(2c+3)=0

We multiply parentheses

5c-4c-(2c+3)+28=0

We get rid of parentheses

5c-4c-2c-3+28=0

We add all the numbers together, and all the variables

-1c+25=0

We move all terms containing c to the left, all other terms to the right

-c=-25

c=-25/-1

c=+25

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