3(b-22)+3(b-2)=36

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Solution for 3(b-22)+3(b-2)=36 equation: 



3(b-22)+3(b-2)=36

We move all terms to the left:

3(b-22)+3(b-2)-(36)=0

We multiply parentheses

3b+3b-66-6-36=0

We add all the numbers together, and all the variables

6b-108=0

We move all terms containing b to the left, all other terms to the right

6b=108

b=108/6

b=18

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