(2/3x+10*2)+(1/3x+5)=90

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Solution for (2/3x+10*2)+(1/3x+5)=90 equation: 



(2/3x+10*2)+(1/3x+5)=90

We move all terms to the left:

(2/3x+10*2)+(1/3x+5)-(90)=0



Domain of the equation: 3x+10*2)!=0

x∈R





Domain of the equation: 3x+5)!=0

x∈R



We add all the numbers together, and all the variables

(2/3x+20)+(1/3x+5)-90=0

We get rid of parentheses

2/3x+1/3x+20+5-90=0

We multiply all the terms by the denominator


20*3x+5*3x-90*3x+2+1=0

We add all the numbers together, and all the variables

20*3x+5*3x-90*3x+3=0

Wy multiply elements

60x+15x-270x+3=0

We add all the numbers together, and all the variables

-195x+3=0

We move all terms containing x to the left, all other terms to the right

-195x=-3

x=-3/-195

x=1/65

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