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5(x-2)+3x=2(x+5)
We move all terms to the left:
5(x-2)+3x-(2(x+5))=0
We add all the numbers together, and all the variables
3x+5(x-2)-(2(x+5))=0
We multiply parentheses
3x+5x-(2(x+5))-10=0
We calculate terms in parentheses: -(2(x+5)), so:We add all the numbers together, and all the variables
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
8x-(2x+10)-10=0
We get rid of parentheses
8x-2x-10-10=0
We add all the numbers together, and all the variables
6x-20=0
We move all terms containing x to the left, all other terms to the right
6x=20
x=20/6
x=3+1/3
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