Y+1=-(2/5)(x-3)

Solution for Y+1=-(2/5)(x-3) equation:

+1=-(2/5)(Y-3)

We move all terms to the left:

+1-(-(2/5)(Y-3))=0


Domain of the equation: 5)(Y-3))!=0

Y∈R


We add all the numbers together, and all the variables

-(-(+2/5)(Y-3))+1=0

We multiply parentheses ..

-(-(+2Y^2+2/5*-3))+1=0

We multiply all the terms by the denominator


-(-(+2Y^2+2+1*5*-3))=0


We calculate terms in parentheses: -(-(+2Y^2+2+1*5*-3)), so:

-(+2Y^2+2+1*5*-3)

We get rid of parentheses

-2Y^2-2+3-1*5*

We add all the numbers together, and all the variables

-2Y^2

Back to the equation:

-(-2Y^2)


We get rid of parentheses

2Y^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{0}{4}=0$