(c+3)-2-(1-3c)=4

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Solution for (c+3)-2-(1-3c)=4 equation: 



(c+3)-2-(1-3c)=4

We move all terms to the left:

(c+3)-2-(1-3c)-(4)=0

We add all the numbers together, and all the variables

(c+3)-(-3c+1)-2-4=0

We add all the numbers together, and all the variables

(c+3)-(-3c+1)-6=0

We get rid of parentheses

c+3c+3-1-6=0

We add all the numbers together, and all the variables

4c-4=0

We move all terms containing c to the left, all other terms to the right

4c=4

c=4/4

c=1

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