17=3(c+3)-c

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Solution for 17=3(c+3)-c equation: 



17=3(c+3)-c

We move all terms to the left:

17-(3(c+3)-c)=0



We calculate terms in parentheses: -(3(c+3)-c), so:

3(c+3)-c

We add all the numbers together, and all the variables

-1c+3(c+3)

We multiply parentheses

-1c+3c+9

We add all the numbers together, and all the variables

2c+9

Back to the equation:

-(2c+9)



We get rid of parentheses

-2c-9+17=0

We add all the numbers together, and all the variables

-2c+8=0

We move all terms containing c to the left, all other terms to the right

-2c=-8

c=-8/-2

c=+4

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