(2/3)x+(2/3)+(1/5)x=(2/3)x

Solution for (2/3)x+(2/3)+(1/5)x=(2/3)x equation:

(2/3)x+(2/3)+(1/5)x=(2/3)x

We move all terms to the left:

(2/3)x+(2/3)+(1/5)x-((2/3)x)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x+(+1/5)x-((+2/3)x)+(+2/3)=0

We multiply parentheses

2x^2+x^2-((+2/3)x)+(+2/3)=0

We get rid of parentheses

2x^2+x^2-((+2/3)x)+2/3=0

We calculate fractions


2x^2+x^2=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$