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(4/5)x+(2/3)+(1/5x)=x
We move all terms to the left:
(4/5)x+(2/3)+(1/5x)-(x)=0
Domain of the equation: 5)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+4/5)x+(+1/5x)-x+(+2/3)=0
We add all the numbers together, and all the variables
-1x+(+4/5)x+(+1/5x)+(+2/3)=0
We multiply parentheses
4x^2-1x+(+1/5x)+(+2/3)=0
We get rid of parentheses
4x^2-1x+1/5x+2/3=0
We calculate fractions
There is no solution for this equation
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