(4/5)x+(2/3)+(1/5)x=x

Solution for (4/5)x+(2/3)+(1/5)x=x equation:

(4/5)x+(2/3)+(1/5)x=x

We move all terms to the left:

(4/5)x+(2/3)+(1/5)x-(x)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/5)x+(+1/5)x-x+(+2/3)=0

We add all the numbers together, and all the variables

-1x+(+4/5)x+(+1/5)x+(+2/3)=0

We multiply parentheses

4x^2+x^2-1x+(+2/3)=0

We get rid of parentheses

4x^2+x^2-1x+2/3=0

We multiply all the terms by the denominator


4x^2*3+x^2*3-1x*3+2=0

Wy multiply elements

12x^2+3x^2-3x+2=0

We add all the numbers together, and all the variables

15x^2-3x+2=0

a = 15; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·15·2
Δ = -111
Delta is less than zero, so there is no solution for the equation