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x-2/4x+1=x+3/x=
We move all terms to the left:
x-2/4x+1-(x+3/x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-2/4x-(+x+3/x)+1=0
We get rid of parentheses
x-2/4x-x-3/x+1=0
We calculate fractions
x-x+(-2x)/4x^2+(-12x)/4x^2+1=0
We add all the numbers together, and all the variables
(-2x)/4x^2+(-12x)/4x^2+1=0
We multiply all the terms by the denominator
(-2x)+(-12x)+1*4x^2=0
Wy multiply elements
4x^2+(-2x)+(-12x)=0
We get rid of parentheses
4x^2-2x-12x=0
We add all the numbers together, and all the variables
4x^2-14x=0
a = 4; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·4·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*4}=\frac{0}{8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*4}=\frac{28}{8} =3+1/2 $
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