(16-4x)(4-x)=0

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Solution for (16-4x)(4-x)=0 equation: 



(16-4x)(4-x)=0

We add all the numbers together, and all the variables

(-4x+16)(-1x+4)=0

We multiply parentheses ..

(+4x^2-16x-16x+64)=0

We get rid of parentheses

4x^2-16x-16x+64=0

We add all the numbers together, and all the variables

4x^2-32x+64=0

a = 4; b = -32; c = +64;
Δ = b2-4ac
Δ = -322-4·4·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{32}{8}=4$

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