3(x-2)-6(3-2x)=3(5x-2)+3(2x-x)

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Solution for 3(x-2)-6(3-2x)=3(5x-2)+3(2x-x) equation: 



3(x-2)-6(3-2x)=3(5x-2)+3(2x-x)

We move all terms to the left:

3(x-2)-6(3-2x)-(3(5x-2)+3(2x-x))=0

We add all the numbers together, and all the variables

3(x-2)-6(-2x+3)-(3(5x-2)+3(+x))=0

We multiply parentheses

3x+12x-(3(5x-2)+3(+x))-6-18=0



We calculate terms in parentheses: -(3(5x-2)+3(+x)), so:

3(5x-2)+3(+x)

We multiply parentheses

15x+3x-6

We add all the numbers together, and all the variables

18x-6

Back to the equation:

-(18x-6)



We add all the numbers together, and all the variables

15x-(18x-6)-24=0

We get rid of parentheses

15x-18x+6-24=0

We add all the numbers together, and all the variables

-3x-18=0

We move all terms containing x to the left, all other terms to the right

-3x=18

x=18/-3

x=-6

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