4(w-2)+3(w+5)=2(w+2)-3(w-4)+17

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Solution for 4(w-2)+3(w+5)=2(w+2)-3(w-4)+17 equation:



4(w-2)+3(w+5)=2(w+2)-3(w-4)+17
We move all terms to the left:
4(w-2)+3(w+5)-(2(w+2)-3(w-4)+17)=0
We multiply parentheses
4w+3w-(2(w+2)-3(w-4)+17)-8+15=0
We calculate terms in parentheses: -(2(w+2)-3(w-4)+17), so:
2(w+2)-3(w-4)+17
We multiply parentheses
2w-3w+4+12+17
We add all the numbers together, and all the variables
-1w+33
Back to the equation:
-(-1w+33)
We add all the numbers together, and all the variables
7w-(-1w+33)+7=0
We get rid of parentheses
7w+1w-33+7=0
We add all the numbers together, and all the variables
8w-26=0
We move all terms containing w to the left, all other terms to the right
8w=26
w=26/8
w=3+1/4

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