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(10x+6)(6x+4)=90
We move all terms to the left:
(10x+6)(6x+4)-(90)=0
We multiply parentheses ..
(+60x^2+40x+36x+24)-90=0
We get rid of parentheses
60x^2+40x+36x+24-90=0
We add all the numbers together, and all the variables
60x^2+76x-66=0
a = 60; b = 76; c = -66;
Δ = b2-4ac
Δ = 762-4·60·(-66)
Δ = 21616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{21616}=\sqrt{16*1351}=\sqrt{16}*\sqrt{1351}=4\sqrt{1351}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-4\sqrt{1351}}{2*60}=\frac{-76-4\sqrt{1351}}{120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+4\sqrt{1351}}{2*60}=\frac{-76+4\sqrt{1351}}{120} $
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