# (a+2)*(a+3)=3

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## Solution for (a+2)*(a+3)=3 equation:

(a+2)(a+3)=3
We move all terms to the left:
(a+2)(a+3)-(3)=0
We multiply parentheses ..
(+a^2+3a+2a+6)-3=0
We get rid of parentheses
a^2+3a+2a+6-3=0
We add all the numbers together, and all the variables
a^2+5a+3=0
a = 1; b = 5; c = +3;Δ = b2-4acΔ = 52-4·1·3Δ = 13The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{13}}{2*1}=\frac{-5-\sqrt{13}}{2}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{13}}{2*1}=\frac{-5+\sqrt{13}}{2}$

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