# (2x-1)(x+17)=0

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## Solution for (2x-1)(x+17)=0 equation:

(2x-1)(x+17)=0
We multiply parentheses ..
(+2x^2+34x-1x-17)=0
We get rid of parentheses
2x^2+34x-1x-17=0
We add all the numbers together, and all the variables
2x^2+33x-17=0
a = 2; b = 33; c = -17;Δ = b2-4acΔ = 332-4·2·(-17)Δ = 1225The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-35}{2*2}=\frac{-68}{4} =-17$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+35}{2*2}=\frac{2}{4} =1/2$

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