(2x-1)(x+17)=0

Solution for (2x-1)(x+17)=0 equation:

(2x-1)(x+17)=0

We multiply parentheses ..

(+2x^2+34x-1x-17)=0

We get rid of parentheses

2x^2+34x-1x-17=0

We add all the numbers together, and all the variables

2x^2+33x-17=0

a = 2; b = 33; c = -17;
Δ = b2-4ac
Δ = 332-4·2·(-17)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-35}{2*2}=\frac{-68}{4}
=-17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+35}{2*2}=\frac{2}{4}
=1/2
$