2x2=300

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Solution for 2x2=300 equation:



2x^2=300
We move all terms to the left:
2x^2-(300)=0
a = 2; b = 0; c = -300;
Δ = b2-4ac
Δ = 02-4·2·(-300)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{6}}{2*2}=\frac{0-20\sqrt{6}}{4} =-\frac{20\sqrt{6}}{4} =-5\sqrt{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{6}}{2*2}=\frac{0+20\sqrt{6}}{4} =\frac{20\sqrt{6}}{4} =5\sqrt{6} $

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