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(10/3)y=90
We move all terms to the left:
(10/3)y-(90)=0
Domain of the equation: 3)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+10/3)y-90=0
We multiply parentheses
10y^2-90=0
a = 10; b = 0; c = -90;
Δ = b2-4ac
Δ = 02-4·10·(-90)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*10}=\frac{-60}{20} =-3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*10}=\frac{60}{20} =3 $
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