If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(3x+6)(3x-9)=0
We multiply parentheses ..
(+9x^2-27x+18x-54)=0
We get rid of parentheses
9x^2-27x+18x-54=0
We add all the numbers together, and all the variables
9x^2-9x-54=0
a = 9; b = -9; c = -54;
Δ = b2-4ac
Δ = -92-4·9·(-54)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-45}{2*9}=\frac{-36}{18} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+45}{2*9}=\frac{54}{18} =3 $
| 3x/7-15/7=3/14 | | x*x-9=40 | | 8=3(x-5)+5 | | 6=24-d | | 5(f-1)=40 | | -5-2v=3v+10 | | (11+16+x)/3=15 | | 6x+22-3x=7x+2 | | 4x2+10x-14=0 | | X+19=2x+26 | | Y=2x-23/7 | | 11+16+x3=15 | | -10(s+4)=39 | | (2x+6)+x=42 | | 3(2x-0,5)=4-2(1-x) | | 3·(4–x)=-24 | | ((x+3)×2+4)×5-10=50 | | 9x+2=7x+2=180 | | 5z+5=8z-50 | | 8+5,y=23 | | 5x+7=2x13 | | 2,6(x-1)=-6,5(x+1)-0,5(x-7,8) | | 3x6=-10 | | 3x-2-2x+5=12-12x/72 | | 5w+10=3w+16 | | 21-x=5x+3 | | 11x-(7x-5)=4x+5 | | 1-5-4x/5=x+2/4-7/10 | | 3c-15=c-9 | | 4-3x/4-2x=1-2x-3/3 | | 3(a-4)=1-0,2(2-a) | | 2(x-1)=-4x+4 |