3(a-4)=1-0,2(2-a)

Solution for 3(a-4)=1-0,2(2-a) equation:

3(a-4)=1-0.2(2-a)

We move all terms to the left:

3(a-4)-(1-0.2(2-a))=0

We add all the numbers together, and all the variables

3(a-4)-(1-0.2(-1a+2))=0

We multiply parentheses

3a-(1-0.2(-1a+2))-12=0


We calculate terms in parentheses: -(1-0.2(-1a+2)), so:

1-0.2(-1a+2)

determiningTheFunctionDomain
-0.2(-1a+2)+1

We multiply parentheses

0.2a-0.4+1

We add all the numbers together, and all the variables

0.2a+0.6

Back to the equation:

-(0.2a+0.6)


We get rid of parentheses

3a-0.2a-0.6-12=0

We add all the numbers together, and all the variables

2.8a-12.6=0

We move all terms containing a to the left, all other terms to the right

2.8a=12.6

a=12.6/2.8

a=4+1/2