y=3((y-3/2))+1

Solution for y=3((y-3/2))+1 equation:

y=3((y-3/2))+1

We move all terms to the left:

y-(3((y-3/2))+1)=0

We add all the numbers together, and all the variables

y-(3((+y-3/2))+1)=0

We multiply all the terms by the denominator


y*2))+1)-(3((+y-3=0

We add all the numbers together, and all the variables

y+y*2))+1)-(3((-3=0

Wy multiply elements

2y^2+y-3=0

a = 2; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·2·(-3)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-5}{2*2}=\frac{-6}{4}
=-1+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+5}{2*2}=\frac{4}{4}
=1
$