0,3(x-2)=0,4(5-x)-4,7

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Solution for 0,3(x-2)=0,4(5-x)-4,7 equation: 



0.3(x-2)=0.4(5-x)-4.7

We move all terms to the left:

0.3(x-2)-(0.4(5-x)-4.7)=0

We add all the numbers together, and all the variables

0.3(x-2)-(0.4(-1x+5)-4.7)=0

We multiply parentheses

0.3x-(0.4(-1x+5)-4.7)-0.6=0



We calculate terms in parentheses: -(0.4(-1x+5)-4.7), so:

0.4(-1x+5)-4.7

We multiply parentheses

-0.4x+2-4.7

We add all the numbers together, and all the variables

-0.4x-2.7

Back to the equation:

-(-0.4x-2.7)



We get rid of parentheses

0.3x+0.4x+2.7-0.6=0

We add all the numbers together, and all the variables

0.7x+2.1=0

We move all terms containing x to the left, all other terms to the right

0.7x=-2.1

x=-2.1/0.7

x=-3+4.4408920985006E-16/0.7

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