(1/4)+(4x/5)=(11/20)

Solution for (1/4)+(4x/5)=(11/20) equation:

(1/4)+(4x/5)=(11/20)

We move all terms to the left:

(1/4)+(4x/5)-((11/20))=0

We add all the numbers together, and all the variables

(+4x/5)+(+1/4)-((+11/20))=0

We get rid of parentheses

4x/5+1/4-((+11/20))=0

We calculate fractions


640x^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

640x^2/()+2=0

We multiply all the terms by the denominator


640x^2+2*()=0

We add all the numbers together, and all the variables

640x^2=0

a = 640; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·640·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{1280}=0$