8(4-2)=4(3-5)+4x

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Solution for 8(4-2)=4(3-5)+4x equation: 



8(4-2)=4(3-5)+4x

We move all terms to the left:

8(4-2)-(4(3-5)+4x)=0

We add all the numbers together, and all the variables

-(4(-2)+4x)+82=0



We calculate terms in parentheses: -(4(-2)+4x), so:

4(-2)+4x

determiningTheFunctionDomain
4x+4(-2)

We add all the numbers together, and all the variables

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

-4x+8+82=0

We add all the numbers together, and all the variables

-4x+90=0

We move all terms containing x to the left, all other terms to the right

-4x=-90

x=-90/-4

x=22+1/2

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