6(2x+6)+5(4x+5)+3=32+65

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Solution for 6(2x+6)+5(4x+5)+3=32+65 equation: 



6(2x+6)+5(4x+5)+3=32+65

We move all terms to the left:

6(2x+6)+5(4x+5)+3-(32+65)=0

We add all the numbers together, and all the variables

6(2x+6)+5(4x+5)+3-97=0

We add all the numbers together, and all the variables

6(2x+6)+5(4x+5)-94=0

We multiply parentheses

12x+20x+36+25-94=0

We add all the numbers together, and all the variables

32x-33=0

We move all terms containing x to the left, all other terms to the right

32x=33

x=33/32

x=1+1/32

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