2-3(b-5)=-21

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Solution for 2-3(b-5)=-21 equation: 



2-3(b-5)=-21

We move all terms to the left:

2-3(b-5)-(-21)=0

We add all the numbers together, and all the variables

-3(b-5)+23=0

We multiply parentheses

-3b+15+23=0

We add all the numbers together, and all the variables

-3b+38=0

We move all terms containing b to the left, all other terms to the right

-3b=-38

b=-38/-3

b=12+2/3

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