(1-0.05x)(1-0.3x)=0

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Solution for (1-0.05x)(1-0.3x)=0 equation: 



(1-0.05x)(1-0.3x)=0

We add all the numbers together, and all the variables

(-0.05x+1)(-0.3x+1)=0

We multiply parentheses ..

(+0x^2+0x+0x+1)=0

We get rid of parentheses

0x^2+0x+0x+1=0

We add all the numbers together, and all the variables

x^2+2x+1=0

a = 1; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-2}{2}=-1$

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