(0,5x+4)(2x+6)-17=39-(x-1)(8-x)

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Solution for (0,5x+4)(2x+6)-17=39-(x-1)(8-x) equation: 



(0.5x+4)(2x+6)-17=39-(x-1)(8-x)

We move all terms to the left:

(0.5x+4)(2x+6)-17-(39-(x-1)(8-x))=0

We add all the numbers together, and all the variables

(0.5x+4)(2x+6)-(39-(x-1)(-1x+8))-17=0

We multiply parentheses ..

(+0x^2+0x+8x+24)-(39-(x-1)(-1x+8))-17=0



We calculate terms in parentheses: -(39-(x-1)(-1x+8)), so:

39-(x-1)(-1x+8)

determiningTheFunctionDomain
-(x-1)(-1x+8)+39

We multiply parentheses ..

-(-1x^2+8x+x-8)+39

We get rid of parentheses

1x^2-8x-x+8+39

We add all the numbers together, and all the variables

x^2-9x+47

Back to the equation:

-(x^2-9x+47)



We get rid of parentheses

0x^2-x^2+0x+8x+9x+24-47-17=0

We add all the numbers together, and all the variables

18x-40=0

We move all terms containing x to the left, all other terms to the right

18x=40

x=40/18

x=2+2/9

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