3b+12=(b-5)

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Solution for 3b+12=(b-5) equation: 



3b+12=(b-5)

We move all terms to the left:

3b+12-((b-5))=0



We calculate terms in parentheses: -((b-5)), so:

(b-5)

We get rid of parentheses

b-5

Back to the equation:

-(b-5)



We get rid of parentheses

3b-b+5+12=0

We add all the numbers together, and all the variables

2b+17=0

We move all terms containing b to the left, all other terms to the right

2b=-17

b=-17/2

b=-8+1/2

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