6(t-6)+6t=4(4t+3)-11

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Solution for 6(t-6)+6t=4(4t+3)-11 equation: 



6(t-6)+6t=4(4t+3)-11

We move all terms to the left:

6(t-6)+6t-(4(4t+3)-11)=0

We add all the numbers together, and all the variables

6t+6(t-6)-(4(4t+3)-11)=0

We multiply parentheses

6t+6t-(4(4t+3)-11)-36=0



We calculate terms in parentheses: -(4(4t+3)-11), so:

4(4t+3)-11

We multiply parentheses

16t+12-11

We add all the numbers together, and all the variables

16t+1

Back to the equation:

-(16t+1)



We add all the numbers together, and all the variables

12t-(16t+1)-36=0

We get rid of parentheses

12t-16t-1-36=0

We add all the numbers together, and all the variables

-4t-37=0

We move all terms containing t to the left, all other terms to the right

-4t=37

t=37/-4

t=-9+1/4

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