((2x-5)*(2x-5))-(x-3)*(3x-2)=((x+3)*(x+3))

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Solution for ((2x-5)*(2x-5))-(x-3)*(3x-2)=((x+3)*(x+3)) equation: 



((2x-5)(2x-5))-(x-3)(3x-2)=((x+3)(x+3))

We move all terms to the left:

((2x-5)(2x-5))-(x-3)(3x-2)-(((x+3)(x+3)))=0

We multiply parentheses ..

((+4x^2-10x-10x+25))-(x-3)(3x-2)-(((x+3)(x+3)))=0



We calculate terms in parentheses: +((+4x^2-10x-10x+25)), so:

(+4x^2-10x-10x+25)

We get rid of parentheses

4x^2-10x-10x+25

We add all the numbers together, and all the variables

4x^2-20x+25

Back to the equation:

+(4x^2-20x+25)





We calculate terms in parentheses: -(((x+3)(x+3))), so:

((x+3)(x+3))

We multiply parentheses ..

((+x^2+3x+3x+9))



We calculate terms in parentheses: +((+x^2+3x+3x+9)), so:

(+x^2+3x+3x+9)

We get rid of parentheses

x^2+3x+3x+9

We add all the numbers together, and all the variables

x^2+6x+9

Back to the equation:

+(x^2+6x+9)



We get rid of parentheses

x^2+6x+9

Back to the equation:

-(x^2+6x+9)



We get rid of parentheses

4x^2-x^2-20x-(x-3)(3x-2)-6x+25-9=0

We multiply parentheses ..

4x^2-x^2-(+3x^2-2x-9x+6)-20x-6x+25-9=0

We add all the numbers together, and all the variables

3x^2-(+3x^2-2x-9x+6)-26x+16=0

We get rid of parentheses

3x^2-3x^2+2x+9x-26x-6+16=0

We add all the numbers together, and all the variables

-15x+10=0

We move all terms containing x to the left, all other terms to the right

-15x=-10

x=-10/-15

x=2/3

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