((2x+1)*(2x+1))-3x(x+4)=((x-2)*(x-2))

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Solution for ((2x+1)*(2x+1))-3x(x+4)=((x-2)*(x-2)) equation: 



((2x+1)(2x+1))-3x(x+4)=((x-2)(x-2))

We move all terms to the left:

((2x+1)(2x+1))-3x(x+4)-(((x-2)(x-2)))=0

We multiply parentheses

-3x^2+((2x+1)(2x+1))-12x-(((x-2)(x-2)))=0

We multiply parentheses ..

-3x^2+((+4x^2+2x+2x+1))-12x-(((x-2)(x-2)))=0



We calculate terms in parentheses: +((+4x^2+2x+2x+1)), so:

(+4x^2+2x+2x+1)

We get rid of parentheses

4x^2+2x+2x+1

We add all the numbers together, and all the variables

4x^2+4x+1

Back to the equation:

+(4x^2+4x+1)





We calculate terms in parentheses: -(((x-2)(x-2))), so:

((x-2)(x-2))

We multiply parentheses ..

((+x^2-2x-2x+4))



We calculate terms in parentheses: +((+x^2-2x-2x+4)), so:

(+x^2-2x-2x+4)

We get rid of parentheses

x^2-2x-2x+4

We add all the numbers together, and all the variables

x^2-4x+4

Back to the equation:

+(x^2-4x+4)



We get rid of parentheses

x^2-4x+4

Back to the equation:

-(x^2-4x+4)



We add all the numbers together, and all the variables

-3x^2-12x+(4x^2+4x+1)-(x^2-4x+4)=0

We get rid of parentheses

-3x^2+4x^2-x^2-12x+4x+4x+1-4=0

We add all the numbers together, and all the variables

-4x-3=0

We move all terms containing x to the left, all other terms to the right

-4x=3

x=3/-4

x=-3/4

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