x(2x+3)-5=7-(3-2x2)

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Solution for x(2x+3)-5=7-(3-2x2) equation: 



x(2x+3)-5=7-(3-2x^2)

We move all terms to the left:

x(2x+3)-5-(7-(3-2x^2))=0

We multiply parentheses

-(7-(3-2x^2))+2x^2+3x-5=0



We calculate terms in parentheses: -(7-(3-2x^2)), so:

7-(3-2x^2)

determiningTheFunctionDomain
-(3-2x^2)+7

We get rid of parentheses

2x^2-3+7

We add all the numbers together, and all the variables

2x^2+4

Back to the equation:

-(2x^2+4)



We add all the numbers together, and all the variables

2x^2+3x-(2x^2+4)-5=0

We get rid of parentheses

2x^2-2x^2+3x-4-5=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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