(30+3m)+(30+4m)=144

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Solution for (30+3m)+(30+4m)=144 equation: 



(30+3m)+(30+4m)=144

We move all terms to the left:

(30+3m)+(30+4m)-(144)=0

We add all the numbers together, and all the variables

(3m+30)+(4m+30)-144=0

We get rid of parentheses

3m+4m+30+30-144=0

We add all the numbers together, and all the variables

7m-84=0

We move all terms containing m to the left, all other terms to the right

7m=84

m=84/7

m=12

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