z2=78

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Solution for z2=78 equation:



z2=78
We move all terms to the left:
z2-(78)=0
We add all the numbers together, and all the variables
z^2-78=0
a = 1; b = 0; c = -78;
Δ = b2-4ac
Δ = 02-4·1·(-78)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{78}}{2*1}=\frac{0-2\sqrt{78}}{2} =-\frac{2\sqrt{78}}{2} =-\sqrt{78} $
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{78}}{2*1}=\frac{0+2\sqrt{78}}{2} =\frac{2\sqrt{78}}{2} =\sqrt{78} $

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